Patchwork [1/3] meta/lib/oe/lsb.py: extract only the needed info from lsb-release

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Submitter Cristian Iorga
Date March 29, 2013, 2:10 p.m.
Message ID <1364566251-16209-1-git-send-email-cristian.iorga@intel.com>
Download mbox | patch
Permalink /patch/47127/
State Accepted
Commit 79a2252545ab50c79e00e02c328191c1163f917d
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Comments

Cristian Iorga - March 29, 2013, 2:10 p.m.
Instead of running lsb_release -a, a lsb_release -ir will be run.
This will prevent issue with distros that don't have all the needed
info in /etc/lsb-release file, in which case lsb_release won't generate
an error code.

Partial fix for [YOCTO #4071]

Signed-off-by: Cristian Iorga <cristian.iorga@intel.com>
---
 meta/lib/oe/lsb.py |    4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

Patch

diff --git a/meta/lib/oe/lsb.py b/meta/lib/oe/lsb.py
index ebf90ba..fed1204 100644
--- a/meta/lib/oe/lsb.py
+++ b/meta/lib/oe/lsb.py
@@ -1,9 +1,9 @@ 
 def release_dict():
-    """Return the output of lsb_release -a as a dictionary"""
+    """Return the output of lsb_release -ir as a dictionary"""
     from subprocess import PIPE
 
     try:
-        output, err = bb.process.run(['lsb_release', '-a'], stderr=PIPE)
+        output, err = bb.process.run(['lsb_release', '-ir'], stderr=PIPE)
     except bb.process.CmdError as exc:
         return None